a^2b^2-7ab+10=0

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Solution for a^2b^2-7ab+10=0 equation:


Simplifying
a2b2 + -7ab + 10 = 0

Reorder the terms:
10 + -7ab + a2b2 = 0

Solving
10 + -7ab + a2b2 = 0

Solving for variable 'a'.

Factor a trinomial.
(2 + -1ab)(5 + -1ab) = 0

Subproblem 1

Set the factor '(2 + -1ab)' equal to zero and attempt to solve: Simplifying 2 + -1ab = 0 Solving 2 + -1ab = 0 Move all terms containing a to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -1ab = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -1ab = 0 + -2 -1ab = 0 + -2 Combine like terms: 0 + -2 = -2 -1ab = -2 Divide each side by '-1b'. a = 2b-1 Simplifying a = 2b-1

Subproblem 2

Set the factor '(5 + -1ab)' equal to zero and attempt to solve: Simplifying 5 + -1ab = 0 Solving 5 + -1ab = 0 Move all terms containing a to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + -1ab = 0 + -5 Combine like terms: 5 + -5 = 0 0 + -1ab = 0 + -5 -1ab = 0 + -5 Combine like terms: 0 + -5 = -5 -1ab = -5 Divide each side by '-1b'. a = 5b-1 Simplifying a = 5b-1

Solution

a = {2b-1, 5b-1}

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